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Enter the density of concrete in kg / m3 average density 2400 kg / m 3 Enter the volume of concrete in m3 The weight of concrete of a given volume and density is Or enter the size of the concrete Enter the width in mm Enter the length in mm Enter the thickness in mm
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To calculate the amount of water required for a concrete mix we need to calculate the quantity of cement required Assume the required amount of cement is 50kg Amount of water required = W/C ratio x cement required = x 50 =25 kg or 25 lit M 15 grade concrete Cement = 1 Part Sand = 2 Part Aggregate = 4 Part
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in this Video Lecture today I will teach you How to calculate Cement Sand and Aggregate for M20 concreteFor Reading Article click on given link https //
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Method A Rodding for maximum aggregates size of mm or less Method B—Jigging for maximum aggregates size greater than mm and not exceeding 125 mm and Method C—Shoveling to determine the loose bulk density of the aggregate Method A Rodding Fill the measure with aggregate in nearly equal three layer Apply 25 evenly distributed
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Permeable Paving Aggregate Bedding Aggregate 4 20mm Sub Base Aggregate 50mm Drain Stones 38mm Drain Stones 19mm Aggregate 14mm Aggregate 10mm Aggregate 10mm Pipe Bedding 6mm Aggregate Type 3 Granular Sub Base Type 1 Granular Sub Base Building Sand Concrete Mix Concrete Products Concrete Blocks 440x290x100mm 350x290x100mm 440x215x140mm 7N 440x215x100mm 440x215x100mm Fair Faced
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For autoclaved aerated concrete and natural stone masonry units calculate the mean of the coefficients of water absorption due to capillary action to the nearest 1 g/ m2 x s0ꞏ5 For clay masonry units calculate the mean of the initial rates of water absorption to the nearest 0 1 kg/ m2 x min 10 Test report
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beam molds of 100 mm 4 in by 100 mm 4 in when the nominal maximum aggregate size does not exceed 38 mm in Specimens shall be cast and hardened with the long axes horizontal • Standard tamping rod 16 mm 5/8 in in diameter and 400 mm 16 in to 600 mm
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Tamping rod 16 mm 5/8 in diameter and approximately 600 mm 24 in long having a hemispherical tip the same diameter as the rod Hemispherical means half a sphere the tip is rounded like half of a ball Vibrator 7000 vibrations per minute 19 to 38 mm 3/4 to 1 1/2 in in diameter and the
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Here we are providing the unit weight of different building materials in alphabetical order for your convenience Conversion 1 kN/m3 = kg/m3 say = 100 kg/m3 round off 1 kg/m3 = lb/ft3
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Overview The coarse aggregate specific gravity test Figure 1 is used to calculate the specific gravity of a coarse aggregate sample by determining the ratio of the weight of a given volume of aggregate to the weight of an equal volume of water It is similar in nature to the fine aggregate specific gravity test
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the number of steps that will be needed Considering an ideal riser of 150 mm the height of the space is divided by the height of each step 2100/150= 14 steps 3 Calculate the height of each riser and width of each tread The height of the space is divided by the number of steps that we have just obtained
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UNIT WEIGHT OF AGGREGATE Kansas Test Method KT 5 1 SCOPE This method of test covers the procedures for determining the unit weight of fine coarse or mixed aggregates The method is applicable to aggregates not exceeding 1 1/2 in mm in nominal maximum size1 KT 5 reflects testing procedures found in AASHTO T 19
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Fine aggregate having size less than mm and coarse aggregate size ranging between more than mm to 256 mm All types of aggregates measured in cubic metre and cubic feet in construction site and we know about 1 cubic meter of 20mm course aggregate weight in kg but sometime when we go through the the interview and facing questions it will ask what is the weight of 1 m3 fine aggregate
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Step 4 Selection of water content and fine to total aggregate ratio The selection of water content is based on Table 2 of IS 10262 2024 Maximum water content for 20 mm aggregate and a slump value of 25 to 50 mm = l But in our problem the value of slump is 100 mm so we need to alter the water content Estimated water content
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Example for concrete calculator in Yards Here I want to show you a calculation for a 20 by 20 and 3 thickness concrete slab 1 20×20 = 400 square feet 2 3/12 = feet 3 400x = 100 cubic feet 4 100 x = cubic yards The above example is solving for volume in yards
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How to Convert Cubic Meter to Ton Register 1 m^3 = ton reg 1 ton reg = m^3 Example convert 15 m^3 to ton reg 15 m^3 = 15 × ton reg = ton reg
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Quantity Calculator fluidadmin 2024 08 04T14 20 32 01 00 If you are unsure how much aggregate you need use our calculator below Select your aggregate type then enter your measurements below Aggregate Type Length Width Depth You will need tonnes of this aggregate type You will need bulk bags of this aggregate type You will need mini bags of this aggregate type
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Nominal maximum size of aggregate = mm Enter unit weight of coarse aggregate if unknown use 1500 to 1900 kg/m 3 for normal weight aggregate = kg/m 3 Enter fineness modulus of fine aggregate = Enter from Table above volume of coarse aggregate per unit volume of concrete = Enter specific gravity Saturated Surface Dry SSD of coarse aggregate if unknown use to for normal
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ounce [oz] of Gravel Dolomite fits into 1 cubic inch pounds [lbs] of Gravel Dolomite fit into 1 cubic foot Gravel Dolomite weighs gram per cubic centimeter or 1 865 kilogram per cubic meter density of gravel Dolomite is equal to 1 865 kg/m³ In Imperial or US customary measurement system the density is equal
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It is the weight of aggregate needed to fill a unit volume of the container It helps to convert quantities by weight to by volume It also indicates the aggregate grading and shape Bulk Density = Weight of aggregate / Container of unit volume Unit Kg/m3 or lb/ft3 Essential Points Bulk density is equal to mass if the volume is unit
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Let s imagine that I want to fill a space measuring 40 ft³ with a custom aggregate costing $20 per ton I am unsure of its density but when buying by bulk the sand weighs 240 pounds per 4 cubic feet
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Length Mtr X Width Mtr X Thick mm X 8 = Weight Per Piece Length ft X Width ft X Thick inch X 3 /4 = Weight Per Piece HEXAGONAL BAR DIA mm X DIA mm X = WT PER Mtr Dia mm X Dia mm X = Wt Per foot BRASS SHEET WEIGHT KGS = LENGTH MM X BREADTH MM X 0 0000085 X THICKNESS Example The weight of
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The calculator does the following conversions for you $$1 ft = 12 in = yd = cm = m$$ $$1 t = 2024 lb = long t = 907 kg$$ We think that our pea gravel calculator is a powerful online tool that can help you find out how many bags of gravel you need eliminating wasted stones and of course save you money
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This is one of the heaviest boulder materials you might encounter Multiply 400 x and you get 69 000 pounds Since 1 ton weighs 2 000 pounds you divide 69 000 by 2 000 and get tons The tonnage will determine whether or not you can move the boulder on your own
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Cubic meters of water to tonnes 1 cubic meter of water = 1 tonne cubic meters of water = tonnes 1 1 / 5 cubic meters of water =
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Density of Cement = 1440 kg/m3 Sand Density = 1450 1500 kg/m3 Density of Aggregate = 1450 1550 kg/m3 How many KG in 1 bag of cement = 50kg Cement quantity in litres in 1 bag of cement = litres 1 Bag of cement in cubic metres = cubic meter How many CFT Cubic Feet = CFT Numbers of Bags in 1 cubic metre cement = Bags
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The weight of aggregate applied in this area is obtained and converted to units of pounds per square yard Good lighting is recommended and care should be taken to place the aggregate only one stone deep The quantity of aggregate needed to cover one square yard of roadway can also be determined in terms of volume as shown in Equation
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The unit weight of light weight aggregate concrete will vary on a per project basis depending on the source of the light weight aggregates Controlled density mixes shall be used for light weight aggregates concretes Background The unit weight of concrete is primarily affected by the unit weight of the aggregate which varies by geographical location and increases with concrete compressive
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The basis of arriving at a correct and reasonable rate per unit Work or Supply for a particular item following its specification and Two types of aggregate like 20 mm 10 mm size this ratio 60 % of total aggregate 20mm size 40 % of total aggregate 20mm size 20 mm aggregate = Labour for Rate Analysis of Concrete As per calculation of rate analysis in labour consumption per
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Unit weight of Steel Bar in Kgs = D^2 /162 Where D is the Diameter of the Steel Bar in mm Remember To calculate the unit weight length L becomes unity Weight of Steel Bar = [ D ^2 L / ] in Kg and Length L in m Weight of Steel Bar = [ D ^2 L / 533] in Kg and Length L in foot Here the density of steel is taken as
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